Method OpenInput
OpenInput(Directory, String, IOContext)
Create an Int32IndexInput on the provided fileName.
Declaration
public abstract Int32IndexInput OpenInput(Directory dir, string fileName, IOContext context)Parameters
| Type | Name | Description |
|---|---|---|
| Directory | dir | |
| System.String | fileName | |
| IOContext | context |
Returns
| Type | Description |
|---|---|
| Int32IndexInput |
